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adarshmsd:
Very easy
Take numbers as a-3d,a-d,a+d,a+3d
And then solve it as per the question
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HERE IS YOUR ANSWER
Let the consecutive number be
= a-3d a-d a+d a+3d
= sum is given as 37
= 4a = 37 a = 37/4
=Given ratio of products as 7:15
=(a-3d) (a+3d)/(a-d) (a+d) = 7/15
=15×(a^2-9d^2) = 7×(a^2-d^2)
=a^2 = 16d^2
=d= a/4 or -a/4
=d= 37/16 or -37/16
Therefore,the numbers (by taking positive value for d) are 37/16 111/16 185/16 259/16
NOTE:AP may be formed by reversing the number also (by taking negative value for d).
HOPE THIS HELPS....
Let the consecutive number be
= a-3d a-d a+d a+3d
= sum is given as 37
= 4a = 37 a = 37/4
=Given ratio of products as 7:15
=(a-3d) (a+3d)/(a-d) (a+d) = 7/15
=15×(a^2-9d^2) = 7×(a^2-d^2)
=a^2 = 16d^2
=d= a/4 or -a/4
=d= 37/16 or -37/16
Therefore,the numbers (by taking positive value for d) are 37/16 111/16 185/16 259/16
NOTE:AP may be formed by reversing the number also (by taking negative value for d).
HOPE THIS HELPS....
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