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Answered by
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Answer:
a> x^2+4xy+y^2
b> -a+15b+26
c> 2x^2-5y^2+11xy
Step-by-step explanation:
a> (x^2+xy+y^2)-(z)= 2x^2+3xy
z= (2x^2+3xy)-(x^2+xy+y^2)
z= (2x^2-x^2)+(3xy+xy)+(y^2)
z= (x^2)+(4xy)+(y^2)
z= x^2+4xy+y^2
b> (2a+8b+10)-(z)= -3a+7b+16
z= 2a+8b+10+(-3a+7b+16)
z= 2a+8b+10-3a+7b+16
z= (2a-3a)+(8b+7b)+(10+16)
z= -a+15b+26
c> (3x^2-4y^2+5xy-20)-(z)= (-x^2-y^2+6xy+20)
z= (3x^2-4y^2+5xy-20)+(-x^2-y^2+6xy+20)
z= 3x^2-4y^2+5xy-20-x^2-y^2+6xy+20
*-20+20= 0
z= (3x^2-x^2)-(4y^2-y^2)+(5xy+6xy)+(0)
z= 2x^2-5y^2+11xy
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