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Find the perimeter of the rectangle whose length is 40 cm and diagonal is 41cm.
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Step-by-step explanation:
ANSWER IS 98
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Answered by
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Answer:
let the breadth be x
length is 40 cm and diagonal(hypotenuse) is 41cm
by using Pythagoras theorem
41 sq.= 40sq.+x sq.
1681=1600+ x sq.
81=x sq
9=x
perimeter of rectangle=2(9+40)
=98
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