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Answer:
u=72km/h =72×1000÷3600=20m/s
v =0 (applied brake)
s=10m(distance)
Now using (v²=u²+2as)
(0)²=(20)²+2(-a) ×10 (-a becz retardation takes place)
0=400-20a
0-400=-20a
-400=20a=-400÷20=20
so retardation will be 20m/s....
aayush8734:
thx
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