pls answer it guys if it genius
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Please mark as brainliest.
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tan A=15/8=P/B
H=√(B^2 + P^2). (Pythagoras theorum)
=√64+225
=√289
=17
sec A=H/B=17/8
cosec A=H/P=17/15
sin A=P/H=15/17
cos A=B/H=8/17
now,
(8secA+15cosecA)/(sinA+cosA)
(8×17/8 + 15×17/15)/(15/17 + 8/17)
(17+17)/(23/17)
(34×17)/23
578/23 ........is the answer
H=√(B^2 + P^2). (Pythagoras theorum)
=√64+225
=√289
=17
sec A=H/B=17/8
cosec A=H/P=17/15
sin A=P/H=15/17
cos A=B/H=8/17
now,
(8secA+15cosecA)/(sinA+cosA)
(8×17/8 + 15×17/15)/(15/17 + 8/17)
(17+17)/(23/17)
(34×17)/23
578/23 ........is the answer
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