Question

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Answer 1

Answer:

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Step-by-step explanation:

Given: In an isosceles triangle ABC with AB = AC, BD and CE are two medians. To Prove: BD = CE Proof: In ∆ABC, ∵ AB = AC ∴ ∠BC = ∠ACB ...(1) | Angles opposite to equal sides of a triangle are equal Also, | Halves of equals are equal ⇒ BE = CD ...(2) | ∵ BD and CE are two medians Now, in ∆BDC and ∆CEB,

Answer 2

Step-by-step explanation:

hope will help you

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