Question

Pls answer. it's really urgent.​

Answer 1

Produce CD to cut AB at E. 

Now, in ∆BDE, we have, 

Exterior ∠CDB=∠CEB+∠DBE 

⇒x=∠CEB+45 …..(i)

In ∆AEC, we have, 

Exterior ∠CEB=∠CAB+∠ACE 

=55+30=85

Putting ∠CEB=85 in (i), we get, 

x=85+45=130

∴x=130