Question

pls answer me as soon as possible it's urgent and it from ch 12 class 10 ICSE syllabus (radioactivity)​ I only need the process (do not attempt the question if you don't know the ans) otherwise I will report your answer​

Answer 1

Explanation:

1)

mass released =0.2 a.m.i

mass defect will be converted into energy

energy released =0.2×931Mev

=186 M ev (approx)

2)

same like the above one

energy released = 0.265×931.5

= 24.7 MeV