Question

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Answer 1

Answer:

Extend LK to meet line GF at point P.

Step-by-step explanation:

From figure, CD || GF, so, alternate angles are equal.

 ∠CHG =∠HGP = 60°  ∠HGP =∠KPF = 60°

[Corresponding angles of parallel lines are equal]  Hence,

∠KPG =180 – 60  = 120°

∠GPK = ∠AKL= 120°

[Corresponding angles of parallel lines are equal]  

∠AKH = ∠KHD = 25° [alternate angles of parallel lines]  Therefore,

∠HKL = ∠AKH + ∠AKL

= 25 + 120

 = 145

Answer 2

From figure, CD || GF, so, alternate angles are equal.

∠CHG =∠HGP = 60°

∠HGP =∠KPF = 60° [Corresponding angles of parallel lines are equal]

Hence,

∠KPG =180 – 60 = 120°

∠GPK = ∠AKL= 120°

[Corresponding angles of parallel lines are equal]

∠AKH = ∠KHD = 25° [alternate angles of parallel lines]

Therefore, ∠HKL = ∠AKH + ∠AKL

= 25 + 120

= 145° Answer

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