Question

pls answer me fast pls all the 2 quetions plssss

Answer 1

here is the answer of the question

Answer 2

q(p²-1)=2p

putting the given values we get

=(sec α+ cosec α)[(sin α+ cos α)²2 - 1]

=(sec α + cosec α) [(sin² α+cos²α+2sin αcos α)-1]

=(sec α + cosec α) (2sin αcos α)

=(sec α )(2sin αcos α)+(cosec α) (2sin αcos α)

=2sin α+2cos

by taking 2 common we get

=2(sin α+ cos α)

=2p