Question

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2. A piece of wire is bent in the shape of an equilateral triangle each of whose sides measures
8.8 cm. This wire is rebent to form a circular ring. What is the diameter of the ring?
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Answer 1

Answer:

according to question :-

since in every case the length of wire will be same whether it is bent in triangle or in circle

now

since it is bent in equilateral triangle :-

each side = 8.8

so perimeter of that triangle :-

8.8+8.8+8.8 = 26.4 cm

now if it is bent in ring then it's lenght will be same

so

perimeter of triangle = circumference of that ring

26.4 / 26.4

so circumference of ring = 26.4

2πr = 26.4

2*22/7 * r = 26.4

r = 26.4*7/44 = 4.2 cm

diameter of ring = r + r = 4.2 + 4.2 = 8.4 cm

hope you understand plz thank my answer

Answer 2

Answer:

nice question

Step-by-step explanation:

side of triangle = 8.8 cm

perimeter of triangle =circumference of circle (acc to ques) =8.8+8.8+8.8=26.4

Circumfrence of cicle=2pi( r)=2*3.14*(r)

r=26.4/6.28

r=4.20cm

diameter=2r=8.4cm