pls answer Q7
explain properly
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Q7)
y(displacement) = a+bt+ct²-dt²
We know, differentiation of displacement gives instantaneous velocity so,
v= dx/dt = dy/dt = da+bt+ct²-dt⁴/dt
=>0+b+2ct-4dt³
v =>b+2ct-4dt³
Initial Velocity means t =0
so,
Initial Velocity = b+0+0 = b
Now, again, differentiation of velocity gives acceleration so,
a = dv/dt =db+2ct-4dt³/dt
=>0+2c = 2c
so, the correct option is (3) b,2c
Cheers!
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