Question

pls answer question no.9​

Answer 1

let no. of ₹20 tickets be 'x' and that of ₹40 be 'y'

therefore

x+y=50__(1)

20x+40y=1800__(2)

(1)*20==>20x+20y=1000__(3)

(2)-(3)==>20y=800

==>y=40

put y=40 in (1)

x+40=50

x=10