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Given:- Radius of inner circle
Radius of outer path
To Find:- Area of the path
Formula used:- (Area of outer circle - Area of inner circle)
Area of circle= 2 ×pie× R
2× 22/7 × (11+3=14)
2×22/7×14 =
88 sq. cm.
Area of inner circle = 2×22/7×11=
484/7= 69.14 sq. cm.
Area of the path = 88 sq. cm. - 69.14 sq. cm. = 18.86 sq. CM.
Ans:- 18.86 sq. cm
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