Math, asked by ammar41, 11 months ago

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Answered by anmolt29
1

Let radius of wheel be r cm

given circumference = 120cm

2πr=120

πr=60

r=60/π-(i)

since,

length of arc=2πr∅/360

from (i)

2π.60/π∅/360=16

120∅/360=16

∅/3=16

∅=48°

(i).reflex angle POQ =360°-48°=312°

(ii). Let number of revolution be n

n×2πr=1000

nπr=500

n.π.60/π=500

60n=500

n=500/60

n=8.33

revolutions are 8.33.

(iii). 60/π

=60×7/22

=210/11

=19.01 cm

(iv).since,

area of sector = πr²∅/360

=π.60/π.60/π×48/360

=3600×48/360π

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