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Let radius of wheel be r cm
given circumference = 120cm
2πr=120
πr=60
r=60/π-(i)
since,
length of arc=2πr∅/360
from (i)
2π.60/π∅/360=16
120∅/360=16
∅/3=16
∅=48°
(i).reflex angle POQ =360°-48°=312°
(ii). Let number of revolution be n
n×2πr=1000
nπr=500
n.π.60/π=500
60n=500
n=500/60
n=8.33
revolutions are 8.33.
(iii). 60/π
=60×7/22
=210/11
=19.01 cm
(iv).since,
area of sector = πr²∅/360
=π.60/π.60/π×48/360
=3600×48/360π
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