pls answer the correct one will get 5 stars
chapter laws of motion
class 11
physics iit jee
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Answered by
2
Answer:
Ans is 200N
Explanation:
F b/w A and B is 120N
we know, F=ma
we will take the sum of mass of block B and C because the thread is pulling both the block.
m = 4+2
m = 6kg
F = 120 N
a = F/m
a = 120/6 = 20m/s²
Now we know a
so, now we will take total mass
m=10
now, F=m*a
F= 20*10=200N
Answered by
1
Answer:
200N
Explanation:
T=(4+2)F+4*0/10
120=6F/10
1200/6=F
F=200N
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