Pls answer the question .
Attachments:
Answers
Answered by
0
Answer:
CotB + CotC = 3
Step-by-step explanation:
AD ⊥ BC
in ΔABD
CotB = Base / Perpendicular
=> CotB = BD/AD
=> CotB = BD/4
Similarly in ΔACD
CotB = Base / Perpendicular
=> CotC = CD/AD
=> CotB = CD/4
CotB + CotC = BD/4 + CD/4
=>CotB + CotC = (BD + CD)/4
=> CotB + CotC = (BC)/4
=> CotB + CotC = 12/4
=> CotB + CotC = 3
Similar questions