pls answer the question if you know..pls be truthful guys..dont spam
Attachments:
Answers
Answered by
2
Answer:
Remains unchanged since the charge enclosed has not changed
please like or do something to notify me if it's correct
Answered by
1
Answer:
Reduce by a factor of 4.....
Bcz flux= E.A
E will be Zero bcz it's is hollow sphere so flux depends on area.....
Area=4πr²,in first case r²=2²=4
when radius decreases r²=1²=1
Similar questions