Math, asked by Anonymous, 1 year ago

pls answer the question in detail

Attachments:

Answers

Answered by sharmavijaylaxmi54
1

Answer:

Hey mate

Hope it helps you

Please mark as brainliest

Step-by-step explanation:

Area of semi-circle PQR = ½π(9/2)2

= 81π/8 cm2

Area of region circle, A = π(9/4)2

= 81π/16 cm2

Area of region (B + C) = π(3/2)2

= 9π/4 cm2

Area of region D = ½π(3/2)2

= 9π/8 cm2

Area of shaded region = Area of semicircle - Area of circle - Area of region (B + C) + Area of region D

= 81π/8 - 81π/16 - 9π/4 + 9π/8

= 63π/16 cm2

= 99/8 cm2


Anonymous: thnku
sharmavijaylaxmi54: Welcome
Anonymous: Ok
Answered by BrainalistCrystal
1

Answer:

Area of semi-circle PQR = ½π(9/2)2

= 81π/8 cm2

Area of region circle, A = π(9/4)2

= 81π/16 cm2

Area of region (B + C) = π(3/2)2

= 9π/4 cm2

Area of region D = ½π(3/2)2

= 9π/8 cm2

Area of shaded region = Area of semicircle - Area of circle - Area of region (B + C) + Area of region D

= 81π/8 - 81π/16 - 9π/4 + 9π/8

= 63π/16 cm2

= 99/8 cm2

PLZ MARK AS BRAINLIEST


Anonymous: thnku
BrainalistCrystal: Plz mark as brainleist
Similar questions