pls answer these two questions..
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DE || AQ (Given)
THEREFORE, BY BASIC PROPORTIONALITY THEOREM, PE/EQ = PD/DA....(1)
NOW,
DF || AR (Given)
THEREFORE, BY BASIC PROPORTIONALITY THEOREM, PF/FR = PD/DA.....(2)
EQUATING L.H.S OF (1) & (2),
WE GET, PE/EQ = PF/FR
THEREFORE, BY CONVERSE OF BASIC PROPORTIONALITY THEOREM, EF || QR
HENCE PROVED....
Hope It Helps You a Lot!!!! Mark as Brainliest If you Find the Answer Great!!!
THEREFORE, BY BASIC PROPORTIONALITY THEOREM, PE/EQ = PD/DA....(1)
NOW,
DF || AR (Given)
THEREFORE, BY BASIC PROPORTIONALITY THEOREM, PF/FR = PD/DA.....(2)
EQUATING L.H.S OF (1) & (2),
WE GET, PE/EQ = PF/FR
THEREFORE, BY CONVERSE OF BASIC PROPORTIONALITY THEOREM, EF || QR
HENCE PROVED....
Hope It Helps You a Lot!!!! Mark as Brainliest If you Find the Answer Great!!!
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