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arunsgh3376:
In that fig, AB//CD, APQ= 50° and PRD=127°,FIND x AND y
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Answer:
Hey..!
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Given:-
- ∠APQ = 50°
- ∠PRD = 127°
To find:-
- The values of x and y
Solution:-
Now, AB||CD
and PQ is the transversal
Hence, ∠APQ = x (Alternate angles)
50° = x
x = 50°
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Similarly
AB||CD
and PR is the transversal
Hence, ∠APR = ∠PRD (Alternate angles)
∠APR = ∠PRD
50° + y = 127°
y = 127° - 50°
y = 77°
Therefore,
The value of "x = 50°" and "y = 77°"
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