Math, asked by sp218, 1 year ago

pls answer this...

A fruitseller bought 200 oranges for Rs. 120 a score. He found that 25 oranges were rotten. He sold the remaining oranges for Rs. 5 each. Find his profit or loss percentage.

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Answers

Answered by siddhartharao77
63

We know that 1 score = 20.

Given,

⇒ 20 oranges = 120

⇒ 1 orange = 6

Then, 200 oranges = 1200.

So, the cost price = 1200.


Now,

Given that number of oranges rotten = 25.

Then, Number of oranges unrotten = 200 - 25 = 175.

Given that he sold the remaining oranges for 5 each.

So, the selling price = 5 * 175 = 875.


Here, Cost price > Selling price. So, Loss has occured.


We know that Loss = Cost price - Selling price

⇒ 1200 - 875

⇒ 325.


We know that Loss% = (Loss/Cost price) * 100

⇒ (325/1200) * 100

⇒ ~27%.


Therefore, Loss percentage = 27%.


Hope this helps!

Answered by akshit2831
26

Answer:

answer is 27 after rounding of correct answer is 27.08

Step-by-step explanation:

we know that

1 score is of 20 oranges

fruit seller bought=200 oranges

so we have to divide 200 with 20 to get how many scores

so 200/20=10

so 10 scores is eqal to 120*10

so cp is 1200

rotten oranges=25

so fresh oranges are 200-25=175

so our fresh oranges are175

sp of 1 oranges =5

sp of 175 oranges are 175*5=875

so cp is greater than sp so thats why it is loss so we have to find loss

so loss is 1200-875 is 325

so we have to find loss percent

loss percent is loss/cp*100

so 325/1200*100 is 27.08

hence your question is solved

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