pls answer this
as soon as possible
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Let the
•yellow colour thing be "a"
•gorilla be "b"
•banana be "c"
1.
a+a+a=30
3a=30
a=30/3=10
2.
a+b+b=20
10+2b=20
2b=10
b=5
3.
b+c+c=17
5+2c=17
2c=12
c=6
What we need to find out:- a+b×c
according to bodmas rule and the question first we should multiply the numbers and then add.
a+b×c
b=b-a as it doesn't have the necklace....
c=c/2
as the banana is only 1 before they were 2.
a+b×c
10+(5-10)×(6/2)
=10+(-5)(3)
=10-15
=-5
hope it helps you!
cheers!! (:
•yellow colour thing be "a"
•gorilla be "b"
•banana be "c"
1.
a+a+a=30
3a=30
a=30/3=10
2.
a+b+b=20
10+2b=20
2b=10
b=5
3.
b+c+c=17
5+2c=17
2c=12
c=6
What we need to find out:- a+b×c
according to bodmas rule and the question first we should multiply the numbers and then add.
a+b×c
b=b-a as it doesn't have the necklace....
c=c/2
as the banana is only 1 before they were 2.
a+b×c
10+(5-10)×(6/2)
=10+(-5)(3)
=10-15
=-5
hope it helps you!
cheers!! (:
Triyan:
the answer comes in "-"
???
and the banana's present is 1 and before they are 2 I updated the answer
what's the answer!!!
-5
how?!
1 banana so c/2=6/2=3
b=5 a=10 gorilla without compass 5-10=-5
10+(-5)(3)
10-15=-5
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