Question

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Answer 1

Answer:

Surface Area of Tent = xm²(4h + 1)

Step-by-step explanation:

Shape of tent = Cuboidal (Cuboid)

AT Q;

Base of the tent is square.

Side of base = x metres

We know that in a square all the sides are equal.

Therefore,

Length = x metres

Breadth = x metres

Height = h metres

Surface Area of Tent = Lateral Surface Area (LSA) of Cuboid + Area of top of the Cube.

☆ Lateral Surface Area (LSA) of Cuboid

Lateral Surface Area (LSA) of Cuboid = 2h(l +b)

Lateral Surface Area (LSA) of Cuboid = 2 h metres ( x metres + x metres)

Lateral Surface Area (LSA) of Cuboid = 2 hm(2xm)

Lateral Surface Area (LSA) of Cuboid = 2hm X 2xm

Lateral Surface Area (LSA) of Cuboid = 4xhm²

☆ Area of top of the Cuboid (Base of Cuboid is square so top will also be square)

Area of top of the Square = Side ²

Area of top of the Square = xm²

Area of top of the Cuboid = xm²

Therefore,

Surface Area of Tent = 4xhm² + xm²

Surface Area of Tent = xm²(4h + 1)

Hope it helps you.

Thanks

Answer 2

Answer:

hope it helps

thankeww