Physics, asked by tanujasarraf7, 1 month ago

pls answer this fast​

Attachments:

Answers

Answered by barkavaishali
0

I think the answer is 125kw

Answered by YourHelperAdi
1

To find :

The power delivered to the turbine

Given :

  • Mass of water falling per second = 100 kg/s
  • acceleration due to gravity = 10m/s²
  • displacement = 120 m

Formula to be applied :

  • Force = acceleration × mass
  • work = Force × displacement
  • power = Work / second

Solution :

Given, mass per second = 100 kg/s

acceleration due to gravity = 10 m/s²

hence, Force per second = mass × acceleration

 \implies \bold{ force \: ps \:  = 100 \times 10} \\  \implies \boxed{ \boxed{ \bold{ force \: ps \:  = 1000 \: n}}}</strong></p><p><strong>[tex] \implies \bold{ force \: ps \:  = 100 \times 10} \\  \implies \boxed{ \boxed{ \bold{ force \: ps \:  = 1000 \: n}}}

Given, Force ps = 1000 N

displacement = 120 m

hence, work done = Displacement ×force

 \implies \bold{ work \:  = 120 \times 1000} \\   \implies \boxed{ \boxed{ \bold{ \: work \:  = 120000 \: j}}}

hence, Work done = 120000 J

Given, Work done = 120000 J

The whole mass of water in 1 second will deliver the power to turbine in 1 second

hence, Time = 1 s

hence, Power delivered = work/time

 \implies \bold{ \: power \:  = 120000  \div 1} \\  \implies \boxed{ \boxed { \bold{power = 120000 \: w}}}

1 kW = 1000 W

hence, 120000 W = 120 kW

hence, the power delivered = 120 kW

hence, your answer is a) 120 kW

have a great day mate :)

Similar questions