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Hi ,
d/dx ( √x + 2x^3/4 + 3x^5/6 )
= 1/( 2√x)+2×(3/4)x^3/4-1 +3×(5/6)x^5/6-1
= 1/(2√x ) + 3/2 (x^-1/4 ) + ( 5/2 ) ( x^-1/6 )
= 1/( 2√x ) + 3/( 2x^1/4 ) + 5/( 2x^1/6 )
I hope this helps you.
: )
d/dx ( √x + 2x^3/4 + 3x^5/6 )
= 1/( 2√x)+2×(3/4)x^3/4-1 +3×(5/6)x^5/6-1
= 1/(2√x ) + 3/2 (x^-1/4 ) + ( 5/2 ) ( x^-1/6 )
= 1/( 2√x ) + 3/( 2x^1/4 ) + 5/( 2x^1/6 )
I hope this helps you.
: )
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