Question

PLS ANSWER THIS FAST.............I WILL MARK IT AS BRAINLIEST!!!!
The polynomials ky³+3y²-3 and 2y³-5y+k when divided by (y-4)leave the same remainder in each case.find the value of k

Answer 1

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here is your answer⇒

⇒y-4=0

⇒y=0+4

⇒y=4

⇒ky³+3y²-3

⇒k*(4)³+3*(4)²-3=0

⇒k*64 + 3*16-3=0

⇒64k+48 - 3=0

⇒64k=0+3-48

⇒64k= 3-48

⇒64k=- 45

⇒k=-12845/64

further simply this if u can

2y³-5y+k

2*(4)³- 5*4+k=0

2*64+ -20 +k=0

128+-20+k=0

k= 0+20-128

k= 20-128

k= -108

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hope it helps

pls mark as brainliest