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the semiperimeter of triangle is 96cm and its sides are in the ratio3:4:5.find the area of the triangle
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first you need to find the height and base of a triangle and solve it using the formula 1/2base*height
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Let the sides be 3a, 4a and 5a
S = 96
=> ( 3a + 4a + 5a) /2 = 96
=> 12a/2 = 96
=> 6a = 96
=> a = 16
First side = 48 cm
Second side = 64 cm
Third side = 80 cm
Area = sqrt [ 96 × (96 - 48)(96 - 64) (96 - 80)]
= sqrt ( 96 × 48 × 32 × 16)
= sqrt ( 16 × 6 × 16 × 3 × 8 × 4 × 16)
= 16 × sqrt ( 6 × 6 × 4 × 4 × 16)
= 16 × 6 × 4 × 4
= 1536 cm^2
S = 96
=> ( 3a + 4a + 5a) /2 = 96
=> 12a/2 = 96
=> 6a = 96
=> a = 16
First side = 48 cm
Second side = 64 cm
Third side = 80 cm
Area = sqrt [ 96 × (96 - 48)(96 - 64) (96 - 80)]
= sqrt ( 96 × 48 × 32 × 16)
= sqrt ( 16 × 6 × 16 × 3 × 8 × 4 × 16)
= 16 × sqrt ( 6 × 6 × 4 × 4 × 16)
= 16 × 6 × 4 × 4
= 1536 cm^2
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