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In the above figure. ∠ABD = 150° and ∠EBC = 70°
We've to find x.
Then, 150 - x + 70 = 180°
150 + 70 - 180 = x
x = 40°
∠x = ∠y = 40° (alternate interior angles)
We need to find ∠EBA , which is 150 - x.
∠EBA = 110°
∠EBA = z = 110°
Sum of x, y, z = 110 + 40 + 40 = 190°
The answer is (C) 190°.
We've to find x.
Then, 150 - x + 70 = 180°
150 + 70 - 180 = x
x = 40°
∠x = ∠y = 40° (alternate interior angles)
We need to find ∠EBA , which is 150 - x.
∠EBA = 110°
∠EBA = z = 110°
Sum of x, y, z = 110 + 40 + 40 = 190°
The answer is (C) 190°.
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