Question

pls answer this question​

Answer 1

Answer:

260

Step-by-step explanation:

let the smallest no be x

other no.s : (x + 2 ),(x + 4 ),(x + 6 ),(x + 8)

sum of nos = 660

x+2+x+4+x+6+x+8+x=660

5x + 20 = 660

5x = 660 - 20

x = 640/5

x = 128

smallest no = x = 128

largest no = x + 8 = 128 + 8 = 136

sum = 128 + 132

= 260

Answer 2

Step-by-step explanation:

let the 5 consecutive even numbers are -

2x ; 2x+2 ; 2x+4 ; 2x+6 ; 2x+8

A/Q

the sum of 5 consecutive numbers is equal to 660

2x + (2x+2) + (2x+4) + (2x+6) + (2x+8) = 660

10x + 20 = 660

10x = 640

x = 64

greatest number = 2x+8

= 2×64+8

= 132

smallest number = 2x

= 2×64

= 128

sum of greatest and smallest number = 128+132

260