Question

pls answer this question ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

given= AE ll BD ,

AF and BC bisector of <EAB

and <ABD respectively means <EAF =< FAB and <ABC = <CBD

to prove=AF ll BC

proof= given that AE ll BD

so, alternate angle equal

< EAB = <ABD

halves of both is also equal

1/2< EAB = 1/2<ACD

half of <EAB is <FAB and half of < ABD is < ABC

so, <FAB= <ABC

but these are alternate angle of line AF and BC

so alternate angles are equal so, line

AF parallel to line BC

AF ll BC

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hope you understand