Question

pls answer this question

Answer 1

Answer:

answer is 3

transitions are

n5--->4

n4--->3

n3---->2

Explanation:

Answer 2

Given

A hydrogen atom, Having n2=5 and n1=1

Total no of the spectral lines =

(n2−n1)(n2−n1−1)/2

Here n2=5 and n1=1

Therefore the total no of the spectral line

(5−1)(5−1−1)/2

=20/2=10

So, the ten lines is

5→4,5→3,5→2,5→1,4→3,4→2,4→1,3→2,3→1,2→1 are

possible in this case.

Of all this lines only, one's falling in Balmer series are in visible region.

For Balmer series,x=2 and y=3,4,5

Thus,

5→2,4→2,3→2 it shows three lines lie in the visible region.