Math, asked by beantkaurluthra7911, 10 months ago

Find the smallest positive integer n for which (1+i/1-i)n=1

Answers

Answered by sprao53413
0

Answer:

(1+i)^2 /(1-i)^2 = - 1

(1+i/1-i)^4=(-1)^2 =1

Therefore n=4

Answered by gandiharini2007
2

Answer:

Answer is 4

hope it helps u

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