Question

pls answer this question​

Answer 1

Answer:

sorry

Explanation:

Answer 2

$i )5Ω ,5 Ω \: and \: 10Ω \: are \: in \: parallel \: connection \: \\ \: \frac{1}{r1} = \frac{1}{5} + \frac{1}{5} + \frac{1}{10} = \frac{2 + 2 + 1}{10} = \frac{5}{10} = \frac{1}{2} \\ r = 2Ω \\ ii)3Ω \: and \: 6Ω \: are \: in \: parallel \: connection \: \\ \frac{1}{r2} = \frac{1}{3} + \frac{1}{6} = \frac{2 + 1}{6} = \frac{3}{6} = \frac{1}{2} \\ r = 2Ω \\ iii) \: total \: resistance \: = r1 + r2 = 2 + 2 = 4Ω \\ iv) current = \frac{v}{r} = \frac{1.6}{4} = 0.4 \: A$