Question

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Answer 1

Answer:

b k= 2

Step-by-step explanation:

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Answer 2

Answer:

Option (c)

Step-by-step explanation:

Solution :-

Given polynomial is (k²+4)x²+13x+4k

On Comparing this with the standard quadratic Polynomial ax²+bx+c

a = k²+4

b = 13

c = 4k

Let the other zero of the polynomial be A

Then the one of the polynomial = Reciprocal of the other zero = 1/A

We know that

Sum of the Zeroes = -b/a

=> A+(1/A) = -13/(k²+4)

=> (A²+1)/A = -13/(k²+4) -------(1)

Product of the zeroes = c/a

=> A(1/A) = 4k/(k²+4)

=> A/A = 4k/(k²+4)

=> 1 = 4k/(k²+4)

=> k²+4 = 4k

=> k²+4-4k = 0

=>k²-4k+4 = 0

=> k²-2k-2k+4 = 0

=> k(k-2)-2(k-2) = 0

=> (k-2)(k-2) = 0

=> k-2 = 0 or k-2 = 0

=> k = 2

Therefore,k = 2

Answer :-

The value of k for the given problem is 2

Used formulae:-

» The standard quadratic Polynomial is ax²+bx+c

»Sum of the Zeroes = -b/a

»Product of the zeroes = c/a