Question

pls answer this question ⁉️
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Answer 1

Answer:

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Answer 2

Answer:

(x+2) is the HCF of the polynomials (x-4) (2x^2+x-a) and (x+1) (2x^2+bx-12), then what is the value of 5a-6b?

f1(x)=(x-4)(2x2+x-a)

f2(x)=(x+1)(2x2+bx-12)

since(x+2)isHCFx=-2isarootofflandf2

f1(-2)=0

→-6(6-a)=0

9=e+

f2(-2)=0

→-1(-4-2b)=0

⇒b=-2

so, 5a-6b-42

If (x+2) is GCD of

P(x)=(x-4)(2x^2+x-a) then

P(-2)=0

(2-4)(2x4-2-a)-0

(6-a)=0

a=6

If (x+2) is HCF of

G(x)=(x+1)(2x^2-bx-12) then

G(-2)=0

(-2+1)(2x4-bx(-2)-12}=0

-4-2b-0

b=-2

5a-6b-5x6-6x(-2)=30+12=42