Question

pls Answer this question

Answer 1

$\huge{ \boxed{answer:}}$


Perimeter = 34 cm.
Breadth = 5 cm.

Find the length of the diagonal.

Perimeter = 2(length + breadth).
34=2(l+5).
34/2=l+5.
17=l+5.
17-5=l.
length = 12.


Let the measure of the diagonal be 'a' cm.

Then,
According to Pythagoras theorem :


${a}^{2} = {5}^{2} + {12}^{2} \\ {a}^{2} = 25 + 144 \\ {a}^{2} = 169 \\ a = \sqrt{169} \\ a = 13.$


$\boxed{ \therefore \; the \; length \; of \; the \; diagonal \; is \; 13cm}$

Answer 2

Length:-x
breadth:-5cm
perimeter:-34cm

$perimeter \: of \: rectangle \: = 2(l + b)$
➡️34=2(x+5)
➡️17=x+5
➡️12=x

$\boxed{\red{Length=12cm}}$

Now,
✴️✴️Length breadth and diagonal together forms Right angled tirange in which diagonal is HYPOTENUSE.✴️✴️

so,
By Pythagoras theoram
${(diagonal)}^{2} = {l}^{2} + {b}^{2} \\ diagonal = \sqrt{ {(12)}^{2} + {(5)}^{2} } \\ diagonal = \sqrt{169} \\ diagonal = 13cm$
➡️➡️Length of Diagonal is 13 cm.✔️✔️