Question

pls answer this question​

Answer 1

Answer:

CD=2×MC

given that:-

radius of circle = 5cm=AO=OC

AM=8CM

and

AM=OM+AO

THEN

OM =AM-AO

Put the vlues in this equation given above

We Get

=> OM= (8-5) =3CM

we know that;-

OM is perpendicular to the chord CD.

In∆OCM <OMC=90°

using Pythagoras theorem

we get,

OC²=OM²+MC²

CM² = OC² - OM²

Solving this,

CM = 4cm

Hence,

CD= 2 ×CM  = 8 cm

Option (D) is correct

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