Question

pls answer this question asap..​

Answer 1

Answer:

We have,

R={(xy):xy is a square of an integer,x,y€N}

As,x×x=x^2,which is a square of unteger.

(x,x)€R

So,R is reflexive.

Let,(x,y)€R

xy us a square of an integer

yx is a square of an integer

(y,x)€R

R is symmetric.

Let,(x,y)€R & (y,z)€R

xy is square of an integer and yz is square of an integer.

xz must be a square of an integer.

(x,z)€R

R is transitive.

hope it helps you.

☆thanks:)