Question

pls answer this question no 8 quickly pls I will mark you as brilliant. but the answer should be correct and step by step​

Answer 1

☯Answer:

➩336cm²

To find:

Area of trapezium

Given:

Length of parellel sides are 18cm and 20cm.

Height of trapezium is 120cm.

Assumption:

Let AB and CD be x and y respectively

Construction:

Construct a perpendicular from E and F on line AD such like in attached figure.

Concept:

Now the trapezium is divided into a rectangle and 2 triangles so we can find their area separately and then add them.

Solution:

As it is obvious that x+y=2cm

(We subtract 18cm from lower line of trapezium)

Assume that if we join ∆ABF and ∆ECD we get:-

• Height of ∆=120cm
• Base of ∆=x+y=2cm

$\sf \large So \: area \: of \: joint \: \: ∆ = \frac{1}{ \cancel2} \times \cancel 2 \times 120 \\ \\ \sf \large = > 120cm²$

$\sf \large Area \: of \: rectangle=120cm×18cm \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \large=>216cm²$

Total area of trapezium

=area of joint∆+area of rectangle

=120cm²+216cm²

=336cm²

Formula used:

• Area of rectangle=l×B
• Area of Triangle=½×B×H

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Answer 2

☯Answer:

➩336cm²

To find:

Area of trapezium

Given:

Length of parellel sides are 18cm and 20cm.

Height of trapezium is 120cm.

Assumption:

Let AB and CD be x and y respectively

Construction:

Construct a perpendicular from E and F on line AD such like in attached figure.

Concept:

Now the trapezium is divided into a rectangle and 2 triangles so we can find their area separately and then add them.

Solution:

As it is obvious that x+y=2cm

(We subtract 18cm from lower line of trapezium)

Assume that if we join ∆ABF and ∆ECD we get:-

Height of ∆=120cm

Base of ∆=x+y=2cm

\begin{gathered} \sf \large So \: area \: of \: joint \: \: ∆ = \frac{1}{ \cancel2} \times \cancel 2 \times 120 \\ \\ \sf \large = > 120cm²\end{gathered}

Soareaofjoint∆=

2

1

×

2

×120

=>120cm²

\begin{gathered} \sf \large Area \: of \: rectangle=120cm×18cm \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \large= > 216cm²\end{gathered}

Areaofrectangle=120cm×18cm

=>216cm²

Total area of trapezium

=area of joint∆+area of rectangle

=120cm²+216cm²

=336cm²

Formula used:

Area of rectangle=l×B

Area of Triangle=½×B×H