Question

Pls answer this question pls.....

Answer 1

Let no. be (a-d),a,(a+d)
7(a-d) = 3(a+a+d)
7a - 7d = 6a + 3d
a = 10d
So no. are 9d,10d,11d
As no. are consecutive so difference 'd' = 1
So no. are 9,10,11

Answer 2

let the number be X, X+1 and X-1 as they are consecutive,

Then According to Question,.
The smallest no. is X-1 then,

7(X-1)=3(X +X+1)

=>7X-7=3(2X+1)

=>7X-7=6X+6

=>7X-6X=6+7

=>X =13

Therefore the 3 numbers are 12,13,14

Hope This helped you.......