pls answer this question .qs=06 write on a paper and send
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According to Pythagoras theorem,
Base^2+Perepndicular^2=Hypotanuse^2
Therfore 7^2+Perpendicular^2=25^2
PERPENDICULAR^2=625-49
Perpendicular ^2=576
Perpendicular=24
Therefore area=(1/2)*Base*Perpendicular=1/2*7*24=84
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