Question

pls answer this question using suitable identity ​

Answer 1

Answer:

(203)cube -103cube by 203cube +203cube.....

Answer 2

Answer:

100

Step-by-step explanation:

Formula Used:-

a³-b³=(a-b)(a²+ab+b²)

Here,a=203 and b=103

$\frac{203^{3}-(103)^{3} }{(203)^{2}-(203)(103)+(103)^{2} }$

$\frac{(203)-(103)[(203)^{2}-(203)(103)+(103)^{2}]}{(203)^{2}-(203)(103)+(103)^{2}}$

203-103

100