Question

pls answer this question with step by step explanation,i will mark as brainliest​

Answer 1

AD=BC+CD-AB=h+d-x

so,

${ad}^{2} = {(ab + bc)}^{2} + {cd}^{2} \\ {(x + h)}^{2} = {d}^{2} - {(h + d - x)}^{2}$

now find ×

${ad}^{2} = {(ab + bc)}^{2} + {cd}^{2}$