Math, asked by akshayjustin123, 1 year ago

pls answer this question with step by step explanation,i will mark as brainliest​

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Answered by Anonymous
0

AD=BC+CD-AB=h+d-x

so,

 {ad}^{2}  =  {(ab + bc)}^{2}  +  {cd}^{2}  \\ {(x + h)}^{2}  =  {d}^{2}  -  {(h + d - x)}^{2}

now find ×

 {ad}^{2}  =  {(ab + bc)}^{2}  +  {cd}^{2}  \\

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