the angle of elevation of the top of a vertical tower from a point on the ground is 60.from another point 10 m vertically above the ground, the angle of elevation is 45,find the height of the tower
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Answer:
The height of the tower is 23.66 m
Step-by-step explanation:
Let the height of the tower from ground = x meter
=> height of the tower corresponding to 10 m height point = x - 10
Let the distance between the foot of the tower and these point = y
Hence we got two right angled triangle,
tan60 = x/y
=> √3 = x/y
=> y = x/√3
Also in the second triangle,
tan45 = (x - 10)/y
=> 1 = (x - 10)/y
=> y = x - 10
=> x/√3 = x - 10
=> x = √3x - 10√3
=> x(√3 - 1) = 10√3
=> x(1.732 - 1 ) = 10 x 1.732
=> x = 17.32/0.732 = 23.66
Hence the height of the tower is 23.66 m
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