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100 cm^2
Step-by-step explanation:
Let the area of ∆ABP be 1/2×b1×h1.
Let the area of ∆ABQ be 1/2×b2×h2.
As the two triangles share the same base,we can say b1=b2.
As the question says that the two lines are parallel,we can the distance between them that is the heights of the triangles is also equal(h1=h2).
So the area of ∆ABP=∆ABQ=100cm^2.
Hope my answer helps you my friend.Please make me the brainliest if this really helps you...
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