Question

Pls answer to question 28

Answer 1

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Join B and E.

ABED is a cyclic quadrilateral.

ADE = EBC … (1)

(exterior angle of a cyclic quadrilateral = Interior opposite angle)

Similarly, EFCB is a cyclic quadrilateral.

EBC + CFE = 180o … (2)

(opposite angles of a cyclic quadrilateral are supplementary)

From (1) and (2),

ADE + CFE = 180o

But these are interior angles made by the transversal DF on the same side of the lines AD and CF. Since, these angles are supplementary, therefore,

AD||CF

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Answer 2

Answer:

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Step-by-step explanation:

=>Join B and E.

=>ABED is a cyclic quadrilateral.

= ADE = EBC … (1)

=>(exterior angle of a cyclic quadrilateral = Interior opposite angle)

=>Similarly, EFCB is a cyclic

quadrilateral.

=>EBC + CFE = 180° … (2)

(opposite angles of a cyclic quadrilateral are supplementary)

=>From (1) and (2),

=>ADE + CFE = 180°

=>But these are interior angles made by the transversal DF on the same side of the lines AD and CF. Since, these angles are supplementary, therefore,

=>AD||CF

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