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A piece of metal weighing 100g is heated to 80°C and dropped into 1 kg of cold water in an insulated container at 15°C. If the final temperature of water in the container is 15.69°C, the specific heat of the metal is
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100 x Cm (80-15.69)=1000 x Cw (0.69)
[Cw=1 Calorie/g °C]
=>Cm=10x 0.69/64.31=0.107 Calorie/g °C
=4.186 x 0.107Joule/g°C=0.449 Joule/g°C.
[Cw=1 Calorie/g °C]
=>Cm=10x 0.69/64.31=0.107 Calorie/g °C
=4.186 x 0.107Joule/g°C=0.449 Joule/g°C.
jala07:
Which formula you have used?
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