Question

pls answer urgently step by step​

Answer 1

Answer:

Solution:-

Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m

In one revolution, the road roller will cover an area equal to its lateral surface area.

So, in one revolution the area of the road covered = 2πrh

= 2*22/7*0.42*1

Area of the road in one revolution = 2.64 sq m

Therefore, in 750 revolutions, the area of the road = 2.64*750

= 1980 sq m

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