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AB||CD
in triangle DCB and ABF
BE =CE
angle DCB=angle EBF
DC||AF
angle DCE =BEF
so DCB congruent ABF
so we can say that
CD =BF
so AB=CD =BF
AB+BF=AF
AB+AB=AF
2AB=AF
in triangle DCB and ABF
BE =CE
angle DCB=angle EBF
DC||AF
angle DCE =BEF
so DCB congruent ABF
so we can say that
CD =BF
so AB=CD =BF
AB+BF=AF
AB+AB=AF
2AB=AF
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